Lars Olsen proof of Darboux's Intermediate Value Theorem for Derivatives

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Discussion Overview

The discussion revolves around Lars Olsen's proof of Darboux's Intermediate Value Theorem for derivatives. Participants explore the relationships between the values of the functions involved and the implications of the theorem, focusing on the conditions under which certain inequalities hold.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants express confusion about why ##y## lies between ##f_a(a)## and ##f_a(b)##, questioning the assumptions made regarding the values of the functions.
  • It is noted that ##f_a(b) = f_b(a)##, which leads to the conclusion that ##y## will lie between either ##f_a(a)## and ##f_a(b)## or ##f_b(a)## and ##f_b(b)##.
  • Participants discuss the implications of the Mean Value Theorem, particularly how it relates to the values of ##f_a(b)## and ##f'(c)##, raising questions about the necessity of ##y## lying between certain derivatives.
  • One participant suggests testing the theorem with a specific function, such as ##f(x) = x^2##, to clarify the relationships.
  • There is a recognition that understanding the connections between the values of the functions is crucial, as some participants initially considered them in isolation.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the proof, with some agreeing on certain aspects while others remain uncertain about specific details. The discussion does not reach a consensus on all points raised.

Contextual Notes

There are unresolved questions about the assumptions underlying the relationships between the functions and their derivatives, particularly regarding the conditions under which ##y## is said to lie between specific values.

Hall
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Here is Lars Olsen's proof. I'm having difficulty in understanding why ##y## will lie between ##f_a (a)## and ##f_a(b)##. Initially, we assumed that ##f'(a) \lt y \lt f'(b)##, but ##f_a(b)## doesn't equal to ##f'(b)##.
 
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##y## will lie between ##f_a(a)## and ##f_b(b)##.
We also have by the construction of the functions ##f_a## and ##f_b## that ##f_a(b) = f_b(a)##.
Thus, ##y## will lie between ##f_a(a)## and ##f_a(b)## or between ##f_b(a)## and ##f_b(b)##.

What is it that you do not understand? Can you come up with a differentiable function ##f## for which the above is not true?
 
malawi_glenn said:
##y## will lie between ##f_a(a)## and ##f_b(b)##.
We also have by the construction of the functions ##f_a## and ##f_b## that ##f_a(b) = f_b(a)##.
Thus, ##y## will lie between ##f_a(a)## and ##f_a(b)## or between ##f_b(a)## and ##f_b(b)##.

What is it that you do not understand? Can you come up with a differentiable function ##f## for which the above is not true?
## f_a(a) = f'(a) \lt y \lt f'(b) = f_b(b)##, that is correct. But how ##f_a(b) = f'(b)##?
 
Hall said:
But how fa(b)=f′(b)?
where is that written/used?
In other words, where do you read ##f_a(b) = f_b(b)##?
 
malawi_glenn said:
where is that written/used?
In other words, where do you read ##f_a(b) = f_b(b)##?
I don't know, sir, but I cannot see simply how ##y## lies between ##f_a(a)## and ##f_a(b)##.
 
##f_a(b) = \frac{ f(a) - f(b)}{a-b}##, by Mean Value Theorem there is some ##c \in (a,b)## such that ##f_a(b) = f'(c)##. Why ##y## necessarily need to lie between ##f'(a) and f'(c)##? We assumed it to lie between ##f'(a)## and ##f'(b)##.
 
Hall said:
I don't know, sir, but I cannot see simply how ##y## lies between ##f_a(a)## and ##f_a(b)##.
You have two cases to consider.
As I wrote, which is in the article.:
We have by the construction of the functions ##f_a## and ##f_b## that ##f_a(b) = f_b(a)##.
Thus, ##y## will lie between ##f_a(a)## and ##f_a(b)## or between ##f_b(a)## and ##f_b(b)##.

1672245477224.png


Work it out with the function say ##f(x) = x^2## and let ##a=-1## and ##b=2## or something.
 
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Darboux.jpg
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If ##y## lies between ##f'(a)## and ##f'(b)##, then it is surely to between the end-points of one of the graphs.

It was not very obvious for me to see, I was considering ##f_a(a)## and ##f_a(b)## individually and not in connection with that "or" ##f_b(a)## and ##f_b(a)##.
 
Are you okay with the proof now?
 
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malawi_glenn said:
Are you okay with the proof now?
Yes.
 
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