- #1
yklin_tux
- 7
- 0
Hello I have a question regarding reflected light from a surface of higher index of refraction.
Suppose I have a ideal laser, and an ideal surface with reflection coefficient 0.7 or something like that.
Say I shine my laser directly perpendicular to the surface (at 90 degrees).
I understand some light will go through, but the reflected light will have a 180 degree phase change, and be traveling opposite to the incoming light.
This screams standing wave pattern, but I do not understand the physical interpretation of this.
I get how a standing wave can be formed in a mirror cavity, but in the present situation where I just have light reflecting from a surface, what happens? I know the equation for my electric field will look something like
E = sin(x - wt) + 0.7 sin(x + wt) assuming that k = 1, E0 = 1
And the result of this is a standing wave. In this case, some energy is transmitted into the surface, and the rest is stored in the standing wave?
I understand seeing the reflected light in this case is impossible because it would mean blocking the incoming light, so seeing reflected light is only possible when light is shined at an angle other than 90 degrees.
Actually, plotting the above function in ROOT and making it a histogram, and watching the projections of y (in watching what happens with the wave as time goes on). I see that the wave actually moves, but very slowly? While still modulating amplitude...
I just want to understand what happens in the case of normal incidence because I clearly have two waves traveling in opposite directions with same frequency.
Suppose I have a ideal laser, and an ideal surface with reflection coefficient 0.7 or something like that.
Say I shine my laser directly perpendicular to the surface (at 90 degrees).
I understand some light will go through, but the reflected light will have a 180 degree phase change, and be traveling opposite to the incoming light.
This screams standing wave pattern, but I do not understand the physical interpretation of this.
I get how a standing wave can be formed in a mirror cavity, but in the present situation where I just have light reflecting from a surface, what happens? I know the equation for my electric field will look something like
E = sin(x - wt) + 0.7 sin(x + wt) assuming that k = 1, E0 = 1
And the result of this is a standing wave. In this case, some energy is transmitted into the surface, and the rest is stored in the standing wave?
I understand seeing the reflected light in this case is impossible because it would mean blocking the incoming light, so seeing reflected light is only possible when light is shined at an angle other than 90 degrees.
Actually, plotting the above function in ROOT and making it a histogram, and watching the projections of y (in watching what happens with the wave as time goes on). I see that the wave actually moves, but very slowly? While still modulating amplitude...
I just want to understand what happens in the case of normal incidence because I clearly have two waves traveling in opposite directions with same frequency.