Understanding the Negative Sign in Laser Linewidth Calculation

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The discussion revolves around the calculation of laser linewidth and the interpretation of the negative sign in the formula Δν = -cΔλ/λ². The user questions the physical meaning of the negative sign, noting that an increase in wavelength corresponds to a decrease in frequency. They express confusion about whether to treat Δν as a change in linewidth or as an absolute value. Ultimately, the realization that linewidth is an absolute value of a difference resolves their concerns, leading to a sense of clarity. Understanding the relationship between wavelength and frequency is crucial for accurate laser linewidth calculations.
dziech
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Hi guys,

It's one of the questions I'm asking myself needlessly but I really wonder about this ;)

Say I have a laser at a wavelength λ. I can calculate the frequency by ν=c/λ. Then the linewidth Δν=cΔλ/λ2 that can be found through differentiation of two sides of the equation. The question is, where does the minus go though? It should be Δν=-cΔλ/λ2 should it not? I can't think of what does the negative physically mean here and that's my question.
 
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If the wavelength increases, the frequency decreases, hence the minus sign. That's all !
 
Am I just thinking of this the wrong way? I mean, Δν is a linewidth in frequency. Say it's 60GHz, the Δλ should be like 0.2nm at 1um, but it would be -0.2nm wouldn't it? Or should I think of it as Δν change in linewidth? But that doesn't make obvious sense to me. It's one of the questions I should probably not think about too much but my brain keeps doing things to me ;D
 
differences have a sign: a-b = -(b-a)

width is an absolute value of a difference
 
That clicked! :D I can finally sleep peacefully ;) Thanks!
 
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