Latent Heat Question: Calculate Vaporization Rate & Energy Needed

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SUMMARY

The discussion focuses on calculating the latent heat of vaporization for a substance heated at a constant rate of 75 J/s. The scientist measures that 100 grams of the substance evaporates in 1 minute, leading to the conclusion that the latent heat of vaporization (L) is 45000 J/kg. Consequently, it will take 10 minutes and 45000 J of energy to evaporate 1 kg of the substance. The formula used for these calculations is E = mL.

PREREQUISITES
  • Understanding of the formula E = mL for latent heat calculations
  • Knowledge of units of power (J/s) and energy (J)
  • Basic concepts of mass and its relationship to energy in phase changes
  • Familiarity with the concept of latent heat of vaporization
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  • Research the concept of latent heat and its applications in thermodynamics
  • Learn about the differences between latent heat of fusion and latent heat of vaporization
  • Explore practical applications of latent heat in real-world scenarios, such as refrigeration
  • Investigate how to calculate energy requirements for various phase changes in different substances
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This discussion is beneficial for students studying thermodynamics, scientists conducting experiments involving phase changes, and educators teaching concepts related to heat transfer and energy calculations.

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Homework Statement



A scientist heats up a substance by applying heat at a constant rate of 75 J/s. She measures that
it takes 1 minute for 100 grams of the substance to evaporate. What is the latent of vaporization
of this substance? If she starts with 1 kg of the substance, how long will it take for it to
evaporate and how much energy will it take to evaporate the substance?

Homework Equations



Q=mL?

3. The Attempt at a Solution [/b

I'm not really sure how to use Q=mL. Does 75 J/s go into Q or is Q the total amount of joules. I know m is the mass and L is the specific latent heat.
 
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Bgerst103 said:

Homework Statement



A scientist heats up a substance by applying heat at a constant rate of 75 J/s. She measures that
it takes 1 minute for 100 grams of the substance to evaporate. What is the latent of vaporization
of this substance?

I will use the formula ##E=mL_v## for easiness.
J/s is the unit of power so if you know the power and the time,you should be able to find the energy supplied.
Use##E=mL_v## to find the ##L_v##.
 
adjacent said:
I will use the formula ##E=mL_v## for easiness.
J/s is the unit of power so if you know the power and the time,you should be able to find the energy supplied.
Use##E=mL_v## to find the ##L_v##.

So, 75 x 60 is equal 4500. 4500= (.1kg)(L) -> L=45000. If it takes 1 minute to vaporize 100g it should take 10 minutes for a kg and 45000 J?
 
Bgerst103 said:
So, 75 x 60 is equal 4500. 4500= (.1kg)(L) -> L=45000. If it takes 1 minute to vaporize 100g it should take 10 minutes for a kg and 45000 J?
Correct.
 
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