:Launching a Jet: Understand the Physics of a Catapult

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The discussion focuses on calculating the net force and length of a catapult used to launch a jet aircraft from an aircraft carrier. The net force on the 2000-kg jet is calculated to be 320,000 N, using the formula F=ma with an acceleration of 160 m/s². The length of the catapult is determined to be 320 meters, derived from the equation for distance under constant acceleration. There is a clarification regarding the correct use of the equations, specifically the proper notation for acceleration. Overall, the calculations confirm the physics principles involved in the catapult launch system.
NewJersey
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An aircraft carriers capapult accelerates a 2000-kg jet aircraft from rst to a lauch speed of 320m/s in 2.0s.

a) The net force on the plane is ?
b) the length of the catapult is ?

F= m/a Lenght= at^2/2 vf=vo*at

320m/s= (0) * a * 2.0s
a= 160 m/s

F= 2000kg * 160m/s
= 320,000 N

b at^2/2 160*4/2= 320M

Is this right








The Attempt at a Solution

 
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"F= m/a Lenght= at^2/2 vf=vo*at " ? NOT right.

F=ma.
vf=v0+at.
 
Your solution is correct.
 
ok yeah, I meant to put the + sign instead of *.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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