:Launching a Jet: Understand the Physics of a Catapult

AI Thread Summary
The discussion focuses on calculating the net force and length of a catapult used to launch a jet aircraft from an aircraft carrier. The net force on the 2000-kg jet is calculated to be 320,000 N, using the formula F=ma with an acceleration of 160 m/s². The length of the catapult is determined to be 320 meters, derived from the equation for distance under constant acceleration. There is a clarification regarding the correct use of the equations, specifically the proper notation for acceleration. Overall, the calculations confirm the physics principles involved in the catapult launch system.
NewJersey
Messages
35
Reaction score
0
An aircraft carriers capapult accelerates a 2000-kg jet aircraft from rst to a lauch speed of 320m/s in 2.0s.

a) The net force on the plane is ?
b) the length of the catapult is ?

F= m/a Lenght= at^2/2 vf=vo*at

320m/s= (0) * a * 2.0s
a= 160 m/s

F= 2000kg * 160m/s
= 320,000 N

b at^2/2 160*4/2= 320M

Is this right








The Attempt at a Solution

 
Physics news on Phys.org
"F= m/a Lenght= at^2/2 vf=vo*at " ? NOT right.

F=ma.
vf=v0+at.
 
Your solution is correct.
 
ok yeah, I meant to put the + sign instead of *.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top