Leakage Conductance of Cylindrical Coax Cable

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Homework Help Overview

The discussion revolves around calculating the leakage conductance per meter of a cylindrical coax cable, given specific dimensions and material properties. The problem involves understanding the relationship between resistance and conductance in the context of coaxial cables.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the resistance using a specific formula and questions whether inverting this value yields the correct conductance. They express uncertainty about the role of relative permittivity in their calculations.
  • Some participants question the validity of the resistance value obtained, noting a discrepancy with typical coaxial cable resistance values and suggesting a potential misunderstanding of the problem.
  • Others clarify the distinction between resistance and permittivity, indicating that they are independent properties.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the resistance value and its implications for conductance. Some guidance has been offered regarding the independence of resistance and permittivity, but no consensus has been reached on the original poster's calculations or assumptions.

Contextual Notes

Participants note that typical coaxial cable resistance is around 50 ohms, which raises questions about the high resistance value calculated by the original poster. There is also mention of the insulation resistance being expected to be very high, indicating a potential misunderstanding of the exercise's context.

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Homework Statement



Find the leakage conductance per meter of a cylindrical coax cable whose inner conductor (r1) is 0.125" (3.175*10^-3 m) and whose outer conductor (r2) = 0.5" (1.27*10^-2 m) if the space between them is filled with a material whose: \varepsilon_r = 2 and \sigma_c = 6*10^{-8} \mho /m.

Homework Equations



I used this formula for calculating the resistance of the coax wire:

R = \dfrac{ln (\dfrac{r2}{r1})}{l2\pi\sigma_c}

The Attempt at a Solution



After solving for R, I get


R = \dfrac{ln (\dfrac{1.27*10^{-2}}{3.175*10^{-3}})}{(1)2\pi(6*10^{-8})} = 3.667 M\Omega

My question is, do I just invert R in order to get the line leakage conductance? It seems like I should be using the relative permittivity somewhere in the calculation, but not sure where. Thanks in advance.
 
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I can't comment on the formula, not without looking it up. :smile: But I'll assume you used it correctly. Yes, its reciprocal gives conductance.

Permittivity is a property concerned with capacitance, etc., whereas resistance (i.e., conductance-1 ) does not involve capacitance. They are independent properties of a dielectric, or of any material.
 
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Something seems to be amiss here. I was thinking about it and I remember that typical coax cable resistance is somewhere like 50 ohms. I got this formula from our slides in class. It doesn't make sense that the answer is so high so I think there is something wrong, but honestly I don't know. Any help/suggestions? I think I might have missed something.

I understand that typical coax lines have a characteristic impedance of being 50 ohms, but it still doesn't make sense that the actual wire resistance I calculated is so high. Can someone point me in the right direction? Am I attacking this problem correctly?
 
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The 50 ohms is like the wire resistance, sort of, but at RF. We like it to be predictable so RF loads and sources can be matched to it. The 3.6 Mohms is the insulation resistance; we'd like it to be very high. A few megohms seems low, but this is just an exercise.
 

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