Learning Logs: Solving y=.70+.59x

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Homework Help Overview

The discussion revolves around the application of logarithms in the context of the equation y = 0.70 + 0.59x, specifically focusing on taking the logarithm of both sides. Participants are exploring the properties of logarithms as they relate to this equation.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to take the logarithm of both sides of the equation but struggles with the simplification of log(0.59x). Some participants clarify that the logarithmic property log(ab) = log(a) + log(b) does not apply in this case, leading to questions about the correct approach to simplify log(0.70 + 0.59x).

Discussion Status

The discussion is ongoing, with participants providing guidance on the limitations of logarithmic properties in this context. There is acknowledgment that the equation log(y) = log(0.70 + 0.59x) may be as simplified as possible, but no consensus has been reached on further steps or implications.

Contextual Notes

Participants are operating under the assumption that they need to take the logarithm of both sides for a statistics quiz, but the specific context or reasoning behind this requirement is questioned by one participant.

Jemal
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I'm trying to teach myself logs for a statistics quiz... I know this is probably easy but i never really learned logs.

Homework Statement


I have to take the logarithm of both side of y=.70 + .59x


Homework Equations


n/a

The Attempt at a Solution



y=.70+.59x

So i get Logy= Log.70 + Log (.59x)
Logy = -.1549 + log.59x

I don't know what to do with the log(.59x) Can i separate the .59 and the x somehow?
 
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Jemal said:
y=.70+.59x

So i get Logy= Log.70 + Log (.59x)

No. You can't do this. We only know that log(ab) = log(a) + log(b). The correct equation is:

Log(y) = Log(.70+.59x)

What is it you're trying to do?
 
gb7nash said:
No. You can't do this. We only know that log(ab) = log(a) + log(b). The correct equation is:

Log(y) = Log(.70+.59x)

What is it you're trying to do?

I just need to take the log of both sides and simplify.

So I get log(y) = log(.70+.59x)

I can't seem to find any laws of logs that let's me simplify log(.70+.59x)

Is that how the equation can be left?
 
Pretty much. There's not much else you can do with that equation.
 
gb7nash said:
Pretty much. There's not much else you can do with that equation.

ok thanks a bunch
 
Jemal said:
I have to take the logarithm of both side of y=.70 + .59x
Why do you think you need to do this? What's the context from which this arises?
 

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