Mentz114
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harrylin said:Neither. As remarked by me and 1977ub in preceding posts, it seems as if you privilege the system that you designate "rest system" in comparison to the one that you call "moving system". However, those systems are arbitrary inertial systems, and according to SR they are on equal footing. Both systems use the simultaneity convention that is discussed in §1 of http://fourmilab.ch/etexts/einstein/specrel/www/ . If I correctly understand your train example, it's a simple variant of Einstein's train example, using two clocks at a distance in the train and also two such clocks on the platform, and you designate each as "inertial frame" for measurements. Therefore I disagreed with your comment that"The only measurement that assumes no simultaneity convention is the one in the rest frame.". To the contrary: both frames assume the Poincare-Einstein simultaneity convention.
Once more: that is only true according to the perspective of the platform observer, and the train observer makes the same claim about the train.
You are missing the point. I have an extended object that lies along its local x-axis. Its length is the integral I gave. Then I have an apparatus which is moving inertially along the same axis wrt the object. What happens when the apparatus tries to measure the length of the moving object ? There is no symmetry or ambuguity. Or frame dependence.
Going back to this
##L=\int_0^Ldx##
##L'=\int_0^{L/\gamma}dx'##
##{dx'}^2=\gamma^2(dx^2+\beta^2dt^2)##
So
##L'=\int_0^{L/\gamma}\sqrt{\gamma^2(dx^2+\beta^2dt^2)}##
The ##dt## refers to the rods rest frame and it is the time between measurements. If we set that to zero then ##L'=L##. But now the in the apparatus frame we have ##{dt'}^2=\gamma^2\beta^2dx^2##. So the time gap between the measurements in the apparatus frame is ##dt'=\gamma\beta L##. No problems.
But what happens if I do this procedure to force ##L'=L/\gamma##. Will there be real solution or will ##L/\gamma## be proven to be an unmeasurable quantity ?