Length of a Curve Homework: 0-1, 3ti+8t^(3/2)j+12t^2k

  • Thread starter Thread starter Mugen Prospec
  • Start date Start date
  • Tags Tags
    Curve Length
Click For Summary
SUMMARY

The discussion focuses on calculating the length of a curve defined by the vector function \( \mathbf{r}(t) = 3ti + 8t^{(3/2)}j + 12t^{2}k \) over the interval \( 0 \leq t \leq 1 \). Participants clarify that the correct approach involves taking the derivative of each component, squaring them, and applying the length formula. The expected answer is confirmed to be 15, with a suggestion to factor the quadratic under the radical for simplification. This method ensures accurate computation of the curve's length.

PREREQUISITES
  • Understanding of vector functions and their components
  • Knowledge of calculus, specifically derivatives and integrals
  • Familiarity with the arc length formula in multivariable calculus
  • Ability to factor quadratic expressions
NEXT STEPS
  • Review the arc length formula for vector functions
  • Practice taking derivatives of vector components
  • Learn how to simplify expressions under a radical
  • Explore additional examples of curve length calculations in multivariable calculus
USEFUL FOR

Students studying calculus, particularly those focusing on vector functions and arc length, as well as educators looking for examples to illustrate these concepts.

Mugen Prospec
Messages
42
Reaction score
0

Homework Statement



3ti+ 8t[tex]^{(3/2)}[/tex]j + 12t[tex]^{2}[/tex]k

0 [tex]\leq[/tex] t [tex]\leq[/tex] 1

Homework Equations





The Attempt at a Solution


I thought you are supposed to take the derivative of all three then square that. those all go into the length formula

My book says answer should be 15 but I am not doing something right. my test is tomorrow, can some one give me a walk through for this one.
 
Physics news on Phys.org
I get 15. For this problem, the quantity under the radical is a perfect square quadratic. Try factoring the quadratic before taking the square root.
 
ok I think i got it. thank you
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
Replies
7
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
12
Views
2K