Length of Wire Homework: Find Length with n Cylinders and r,R Radii

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SUMMARY

The length of wire enclosing n identical cylinders with radius r, positioned on a circle of radius R, is given by the formula 2πr + 2nRsin(π/n). This formula accounts for both the straight sections of wire around the cylinders and the curved sections. As the number of cylinders (n) increases, the formula approaches 2π(R + r), indicating the wire's length converges to the circumference of a larger circle encompassing the cylinders. Understanding the relationship between the angles and the sine rule is crucial for deriving this formula.

PREREQUISITES
  • Understanding of basic geometry, specifically circles and triangles.
  • Familiarity with trigonometric functions, particularly sine.
  • Knowledge of limits in calculus.
  • Ability to visualize geometric configurations and relationships.
NEXT STEPS
  • Study the sine rule in depth to apply it effectively in geometric problems.
  • Explore the concept of limits in calculus to understand convergence in mathematical expressions.
  • Practice drawing geometric diagrams to visualize relationships between angles and lengths.
  • Investigate the properties of circles and the implications of enclosing shapes within them.
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Students studying geometry and calculus, particularly those tackling problems involving cylindrical shapes and wire lengths, as well as educators looking for teaching resources on these topics.

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Homework Statement


There are n identicle cylinders attached upright on a board. Each cylinder has a radius r, and the centre of each cylinder's base lie on a large circle of radius R. They are evenly spaced around the circle. A loop of wire encloses the cylinders. Show that the length of the wire is given by [tex]2\pi r + 2nRsin\frac{\pi}{n}[/tex]

The Attempt at a Solution


Im quite lost. I am not even sure where to start. I am not asking for someone to show me the solution, but if somebody could start me in the right direction, that would be great.

Now, in class, we havnt started on limits yet, but i think they may be involved in this.
 
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Draw a picture, for a small values of n like 3 or 4.

The wire is wrapped tight round the cylinders so some parts of it are straight, and other parts are curved round the small cylinders.

You can get some clues from the answer. Try to see how the "2n angles of size pi/n" and the length "2 pi r" relate to your picture.
 
danago, your assumption of this involving limits is correct because as n approaches infinity the length of the wire circumnavigating the cylinders approaches 2(pi)(R+r)

The first part of the formula is straight forward, as the 2(pi)(r) indicates the wire length if it were around a single cylinder.
When having drawn your diagrams, you will have noticed that triangles can be drawn between the area enclosed by the wire, thus the furthermost edge of the triangles plus the 2(pi)(r) will give you the length of the wire. To calculate the furthermost edge of the triangles try using the sine rule (a/sin A = b/sin B = c/sin C)
 

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