Length on vibrating section of violin

AI Thread Summary
The discussion revolves around calculating the length of the vibrating section of a violin string based on its frequency, tension, and linear density. The frequency was initially calculated as 879 Hz using the given wavelength and speed of sound. However, an error occurred in the algebraic manipulation, specifically in the use of linear density, where the user incorrectly divided by L. Correcting this misunderstanding clarified that the linear density should not be divided by L in the velocity expression. The conversation highlights the importance of accurately applying formulas in physics problems.
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Homework Statement


A particularly beautiful note reaching your ear from a rare Stradivarius violin has a wavelength of 39.1 cm. The room is slightly warm, so the speed of sound is 344 m/s.

If the string's linear density is 0.560g/m and the tension is 160N , how long is the vibrating section of the violin string?

Homework Equations


f=c/wavelength
f=sqrt(F/(m/L))/(2L)

The Attempt at a Solution


frequency = (344m/s) /(.391m) = 879Hz
879=sqrt(160/(.000560/L))/(2L)
i converted .560g/m to .000560kg/m because force is in Newtons
did algebra and got that length is 10.81m, which is wrong.
Not sure what I did wrong though.
 
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chicagobears34 said:
879=sqrt(160/(.000560/L))/(2L)
i converted .560g/m to .000560kg/m because force is in Newtons
did algebra and got that length is 10.81m, which is wrong.
Not sure what I did wrong though.
Looks like an arithmetic error. Can't tell what you did wrong if you don't post all your work.
 
You were given the linear density of the string, not its entire mass. So no need to divide it by L in your velocity expression.
 
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yes i was given the linear density, so I shouldn't have done m/L
that's what I what was doing wrong.
Thanks
 
chicagobears34 said:
yes i was given the linear density, so I shouldn't have done m/L
that's what I what was doing wrong.
Thanks
Rats - I noticed that but dismissed it as a typo.
 
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