Lennard-Jones potential graph w/ attractive/repulsive force

AI Thread Summary
The discussion centers on the interpretation of force direction in relation to the equation F = -dΦ/dr. It clarifies that a positive force indicates an attractive interaction between two molecules, while a negative force signifies a repulsive interaction. Specifically, when two molecules are further apart than a certain distance (rm), the force is attractive, and when they are closer, the force becomes repulsive. The key takeaway is that the sign of the force correlates directly with the slope of the potential energy curve, where a negative slope results in a positive force, confirming the attractive nature of the interaction.
destroyer130
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Based on this and the equation F = -d\Phi/dr. I can't visualize what is positive and negative force direction (what is positive direction). So is that just mean whenever the force between 2 molecules (+), it's repulsive; and whenever it's (-), it's attractive? Thanks for checking this out.
 
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destroyer130 said:
View attachment 54775

Based on this and the equation F = -d\Phi/dr. I can't visualize what is positive and negative force direction (what is positive direction). So is that just mean whenever the force between 2 molecules (+), it's repulsive; and whenever it's (-), it's attractive? Thanks for checking this out.
What this graph is telling you is that, if the two molecules are farther apart than rm, the force between them is attractive, but if they are closer together than this, the force is repulsive.
 
What Chestermiller said.

I just want to point out that with the equation you posted the force is attractive when it is positive and repulsive when negative (not the other way around) (When the slope of the potential curve is negative the force is positive)
 
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