Let v(x,t) = u(x+ct) and show that

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1. Homework Statement

NOTE: I realize the following is a partial differential equation, but I believe the answer to my question is a straight forward multi-variate calculus question.

Let v(x,t) = u(x+ct,t) and show that v(x,t) solves the following...

ut = κ uxx ; (-∞<x<∞)

u(x,0) = \phi(x)

NOTE: You may disregard the following, if necessary for you to answer this question:

u(x,0) = \phi(x)

and simply show that v(x,t) solves the following...

ut = κ uxx

ALTERNATIVELY, you may help me by commenting on the correctness of my work below.




2. Homework Equations

See above and below...




3. The Attempt at a Solution

v(x,t) = u(x+ct,t)

v'(x,t) = c u_{x}(x+ct,t) + u_{t}(x+ct,t)

v_{x}(x,t) = c u_{x}(x+ct,t)

v_{xx}(x,t) = c^{2} u_{xx}(x+ct,t)

v_{t}(x,t) = u_{t}(x+ct,t)
 
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Any help on any part will be GREATLY appreciated!
 
Welcome to PF,

jpcjr said:
1. Homework Statement

NOTE: I realize the following is a partial differential equation, but I believe the answer to my question is a straight forward multi-variate calculus question.

Let v(x,t) = u(x+ct,t) and show that v(x,t) solves the following...

ut = κ uxx ; (-∞<x<∞)


Just before we start, are you sure it was not meant to be simply v(x,t) = u(x+ct)? Because I know that a function in which the temporal and spatial dependence are related in this way will satisfy a wave equation, which is given by utt = κuxx. This is different from the PDE that you gave. But anyway, taking what you wrote at face value:


jpcjr said:
ALTERNATIVELY, you may help me by commenting on the correctness of my work below.



Homework Equations



See above and below...

The Attempt at a Solution



v(x,t) = u(x+ct,t)

v'(x,t) = c u_{x}(x+ct,t) + u_{t}(x+ct,t)

v_{x}(x,t) = c u_{x}(x+ct,t)

v_{xx}(x,t) = c^{2} u_{xx}(x+ct,t)

v_{t}(x,t) = u_{t}(x+ct,t)

First of all, I don't think that v' (v "prime") is meaningful here. In single-variable calculus, a prime symbol typically means "derivative with respect to the argument." But this function has two arguments. Since it is a multi-variable function, any derivative is going to be a partial derivative, and you must explicitly specify which variable you are differentiating with respect to. As for your attempt at partial derivatives, my approach would be to write:

u = u(w,t) where w = x+ct

then,

\frac{\partial u}{\partial x} = \frac{\partial u}{\partial w}\frac{\partial w}{\partial x}= \frac{\partial u}{\partial w}

Et cetera for the other derivatives
 
To your first point...

I am sure it is:

Let v(x,t) = u(x+ct,t)

to your second point...

That would mean the following is incorrect, right?

v.sub.x(x,t) = c u.sub.x(x+ct,t)

and should have been...

v.sub.x(x,t) = u.sub.x(x+ct,t)
 
What I was saying was that v_x = u_w, with underscores denoting subscripts.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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