Levi-civita connection assumptions

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SUMMARY

The discussion centers on the Levi-Civita connection in the context of relativity, specifically its derivation and the implications of the torsion-free condition. The covariant derivative is defined as \(\nabla_j V^i=\partial_jV^i+V^k \Gamma^{i}_{kj}\), where \(\Gamma^{i}_{kj}\) is the connection coefficient. It is established that the connection coefficient is torsion-free, leading to the conclusion that the indices of \(\Gamma^{j}_{ir}\) must be symmetric. The uniqueness of the Levi-Civita connection arises from its compatibility with the metric and the zero torsion condition, as noted by the participant Dave.

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In a lot of textbooks on relativity the Levi-Civita connection is derived like this:

V=V^ie_i
dV=dV^ie_i+V^ide_i
dV=\partial_jV^ie_idx^j+V^i \Gamma^{j}_{ir}e_j dx^r
which after relabeling indices:
dV=(\partial_jV^i+V^k \Gamma^{i}_{kj})e_i dx^j

so that the covariant derivative is defined as:

\nabla_j V^i=\partial_jV^i+V^k \Gamma^{i}_{kj}

However, the connection coefficient \Gamma^{i}_{kj} is torsion-free by definition, as de_i=\Gamma^{j}_{ir}e_j dx^r implies that
(1) \partial_r e_i=\Gamma^{j}_{ir}e_j.

If e_i=\partial_i then since \partial_i\partial_r=\partial_r\partial_i then by (1):

\Gamma^{j}_{ir}e_j=\Gamma^{j}_{ri}e_j

or that the bottom two indices are symmetric which is the torsion-free condition.

I have two questions. Is the equation \partial_r e_i=\Gamma^{j}_{ir}e_j true in general for any connection? And also, where did the torsion-free assumption enter into the derivation above?
 
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Hello,

I'm not sure about the derivation you gave, I'm a bit hazy on all this. As far as I know the Levi-Civita connection is, by definition, the (unique) connection which is compatible with the metric and has zero torsion. (Perhaps this is shown in Jost, Differential Geometry or similar.)

Presumably this means that if you remove the zero torsion hypothesis, the connection is no longer uniquely defined (and it is not the L-C connection).

Dave
 

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