How Do You Calculate the Tension in a String Lifting an Accelerating Mass?

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SUMMARY

The tension in a string lifting a 1.65 kg mass that accelerates upwards at 3.10 m/s² can be calculated using Newton's second law. The weight of the mass is 16.17 N, calculated by multiplying the mass (1.65 kg) by the acceleration due to gravity (9.8 m/s²). The net force acting on the mass is the sum of the weight and the force due to the upward acceleration, resulting in a total tension of 21.3 N. The correct approach involves recognizing that the tension must counteract both the weight and provide the additional force for the upward acceleration.

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Homework Statement


A 1.65 kg mass is suspended from a string which is pulled upward. The mass accelerates upwards with an acceleration of 3.10 m/s^2. What is the tension in the string?

Homework Equations



f = ma

The Attempt at a Solution


seems really easy but i can't get the right answer

the regular tension would be 1.65kg * 9.8m/s^2 = 16.17N

if its pulled up 3.1 m/s^2, the forces in that would be 1.65kg * 3.1m/s^2 = 11.05N

then i subtracted the forces to get 5.1, but its wrong.

that wasn't right so i added the forces, still wrong.

then i did the acceleration as a whole, as in 9.8 + 3.1 = 12.9
then found the forces which is 21.3N... still wrong

anyideas? thanks
 
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Draw a free body diagram, and solve the problem as you see the forces there (gravity, upward acceleration included). The acceleration would be modified.
 
iamtrojan3 said:
seems really easy but i can't get the right answer

the regular tension would be 1.65kg * 9.8m/s^2 = 16.17N

yes regular if it was in equilibrium, so just know that is the weight of the mass.


iamtrojan3 said:
if its pulled up 3.1 m/s^2, the forces in that would be 1.65kg * 3.1m/s^2 = 11.05N

3.1 m/s2 is the resultant acceleration, multiplying it by the 1.65kg gives the resultant force.



In your free body diagram, the tension acts upwards while the weight acts downwards. Can you make a relationship between the tension,weight and resultant force? If you can do that, then the question become quite easy.
 

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