Lifting/breaking an object with circular motion

AI Thread Summary
In a centripetal force experiment involving a washer and a stopper, the upward movement of the washer is attributed to increased tension in the rope as the stopper is whirled faster. This tension exceeds the weight of the washer, allowing it to rise. Similarly, when a nut is attached to a rod and whirled, the increasing speed generates a force that eventually leads to the nut breaking due to excessive tension. The discussion emphasizes that tension in the rope increases with speed, which can lead to breaking if it surpasses the material's strength. Understanding these forces is crucial for analyzing the dynamics of circular motion and the effects of tension.
great_scott
Messages
9
Reaction score
0
i have two questions i think are asking almost the same thing.

1) in this typical centripetal force experiment; there are a stopper mass attacthed to one end of a rope and a washer attached to the other end of the rope. as the washer hangs straight down, i start whirling the stopper. after a point, the faster i whirl it, the more the washer goes up. the question is what is the force that pulls the washer upwards? i assume the tension must always be equal to the centripetal force that is created by the weight of the washer so it shouldn't be enough to beat the weight of the washer to lift it.

2)there is a nut or something breakable on an end of a rod and as you whirl the rod vertically keeping the nut in a circular motion. as you do it faster and faster you observe the nut breaks or at least gets damage soon or later. what is the force that breaks the nut?

thanks.
 
Physics news on Phys.org
great_scott said:
the question is what is the force that pulls the washer upwards?
The string tension.
i assume the tension must always be equal to the centripetal force that is created by the weight of the washer so it shouldn't be enough to beat the weight of the washer to lift it.
Don't assume that the tension just equals the weight of the washer. By spinning the stopper faster, you create more tension, which raises the washer.
2)there is a nut or something breakable on an end of a rod and as you whirl the rod vertically keeping the nut in a circular motion. as you do it faster and faster you observe the nut breaks or at least gets damage soon or later. what is the force that breaks the nut?
The faster you whirl the rod, the greater force it must exert on whatever is attached to it. Eventually, something breaks.
 
how do i creat more tension with no additional force? and obviously as the washer goes up it gains some more potential energy so there has got to be a net force that does some work against gravity by raising the washer?
i can actually put it that way what force makes the rope break when i whirl an object attachted to the rope fast enough? let's say vertically and above my head.
 
great_scott said:
how do i creat more tension with no additional force? and obviously as the washer goes up it gains some more potential energy so there has got to be a net force that does some work against gravity by raising the washer?
Tell me how you get the stopper to go faster.
i can actually put it that way what force makes the rope break when i whirl an object attachted to the rope fast enough? let's say vertically and above my head.
When the string tension gets too high, the string breaks. You are pulling on the string with a greater force as you twirl it faster.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top