Lifting container with low pressure that keeps lid on

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SUMMARY

The discussion revolves around calculating the maximum mass of air that can be contained in a 2-litre cooking pot with a diameter of 20 cm and a mass of 300g, while ensuring the lid remains on during lifting. The surrounding pressure is given as 0.9 bar at 19°C. Key equations include the ideal gas law (pV = mRT) and the force balance equation (F = Fp + FG). The participants explore the implications of internal and external pressure on the lid's ability to stay in place, emphasizing the significance of the pot's diameter for calculating force on the lid's surface area.

PREREQUISITES
  • Understanding of the ideal gas law (pV = mRT)
  • Basic principles of fluid mechanics and pressure differentials
  • Knowledge of force balance equations (F = Fp + FG)
  • Ability to calculate force based on pressure and area (F = P*A)
NEXT STEPS
  • Learn how to apply the ideal gas law in practical scenarios
  • Study fluid mechanics principles related to pressure differentials
  • Explore force balance calculations in closed systems
  • Investigate the impact of surface area on pressure forces
USEFUL FOR

This discussion is beneficial for physics students, engineers, and anyone interested in understanding the dynamics of pressure in closed containers, particularly in applications involving buoyancy and force calculations.

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Homework Statement


The question is:

A 2 litre cooking pot (diameter: 20 cm, mass: 300g) is closed with a tight fitting lid, and contains only air. What mass of air can be maximally in the pot so that you can lift the lid, and the pot will move with the lid? Assume the surrounding pressure is p0 = 0.9 bar, and the temperature is 19°C.

Homework Equations



pV=mRT
F = Fp + FG[/B]

The Attempt at a Solution



I'm stuck on the free body diagram for this question. I'm thinking that if the pressure inside the pot is lower than the outside, the lid will stay on as the pot is lifted (obviously). I think this might be the force equation:

F = Fp + FG

where F = force upwards on lid, Fp = force of lower air pressure inside pulling down on lid, and FG = force down on (mass of pot + mass of air) by gravity.

First of all, I'm not sure if that makes any sense. Does it take extra force upwards to compensate for the force pulling down on the lid due to negative air pressure/force pushing down on the lid by the greater outside pressure? Also, how can I figure out any of the forces if the mass of air is unknown? I just don't know where to start and I can find no relevant examples that explain this.
 
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Let C be the container, excluding the lid. To simplify, assume the container is a vertical cylinder and the lid is the whole of the top. What is the net force vector of air pressure on C? To figure that out, consider these sub-questions:

Can we ignore pressure forces on the sides? Why?
What is the net force vector from air pressure on the bottom of C?

Having figured that out, imagine holding the lid so that the container just dangles still and upright in the air. In the light of the answers to the previous sub-questions, what is the maximum weight of C such that it will not fall down?

By the way, the mass of 300g in the question must be the mass excluding the lid, ie the mass of C.

Supplementary question: They have given us the diameter of C. Do we need it? Why/why not?
 
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andrewkirk said:
What is the net force vector of air pressure on C? To figure that out, consider these sub-questions:

Can we ignore pressure forces on the sides? Why?
What is the net force vector from air pressure on the bottom of C?

1. The net force of air pressure on the container is pointing inwards? Since the pressure on the inside is lower than the outside?
2. The pressure on the sides of C does not affect its buoyancy in air?
3. The negative pressure inside C means that the force vector points upwards from the bottom, thus making it more buoyant?

andrewkirk said:
In the light of the answers to the previous sub-questions, what is the maximum weight of C such that it will not fall down?

By the way, the mass of 300g in the question must be the mass excluding the lid, ie the mass of C.

Supplementary question: They have given us the diameter of C. Do we need it? Why/why not?

4. I'm not sure about this one.
5. The diameter of C is used to calculate the force on the surface area of the inside of the lid, with F = P*A.

Am I on the right track? I'm still pretty clueless.
 

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