Light bulb brightness in a circuit

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SUMMARY

The discussion centers on determining which light bulb in a parallel circuit configuration will shine the brightest. The user concludes that bulb P will be the brightest due to the arrangement of bulbs S, T, R, and Q in parallel, resulting in a lower equivalent resistance (Rp). The reasoning is based on the principle that the bulb emitting the most energy per second, measured in watts (joules per second), will shine the brightest. The calculation of equivalent resistance in parallel circuits is confirmed as critical to understanding brightness in this context.

PREREQUISITES
  • Understanding of electrical circuits, specifically parallel circuit configurations.
  • Knowledge of resistance calculations, including the formula for equivalent resistance in parallel circuits.
  • Familiarity with the concept of power in electrical systems, measured in watts.
  • Basic principles of energy conversion from electrical energy to light energy.
NEXT STEPS
  • Study the calculation of equivalent resistance in parallel circuits using formulas like 1/R_total = 1/R1 + 1/R2 + ...
  • Learn about the relationship between power, voltage, and current in electrical circuits, specifically Ohm's Law.
  • Explore the concept of energy conversion efficiency in light bulbs and how it affects brightness.
  • Investigate different types of light bulbs and their power ratings to understand variations in brightness.
USEFUL FOR

Students studying electrical engineering, educators teaching circuit theory, and hobbyists interested in electronics and circuit design.

ghostbuster25
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ok revision question fo me, just want to check my reasonning.

which of te bulbs on the circuit of the attatched file will shine more brightly?

i think p....because s and t r and q are in parrellel which is resistance 1/Rs+Rt+1/Rr+Rq
where Rp is the sum of the resistance of 1/Rs+Rt+1/Rr+Rq over 1 +1/Rp

the resistance of the lower part of the parellel circuit Rs,Rt,Rr and Rq will be greater than the resistance of Rp.

Is this answer and reasoning correct?

many thanks
 

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ghostbuster25 said:
ok revision question fo me, just want to check my reasonning.

which of te bulbs on the circuit of the attatched file will shine more brightly?

i think p....because s and t r and q are in parrellel which is resistance 1/Rs+Rt+1/Rr+Rq
where Rp is the sum of the resistance of 1/Rs+Rt+1/Rr+Rq over 1 +1/Rp

the resistance of the lower part of the parellel circuit Rs,Rt,Rr and Rq will be greater than the resistance of Rp.

Is this answer and reasoning correct?

many thanks

The one that will glow the brightest will give off the most joules of energy per second, assuming that all the light bulbs are the same (ie same amount of electrical energy converted to light energy).

So which resistor is "giving off" the most joules of energy? there is a name for joules of energy per second, do you know what it is and how it is calculated?
 

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