Likelihood of inheriting autosomal dominant diseases

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If one parent has Huntington's disease, the likelihood of inheriting the gene is not a straightforward 50% unless that parent is heterozygous. If the affected parent is homozygous dominant, the chance of passing on the disease increases to 100%. However, the prevalence of homozygous dominant individuals is low, making the assumption of equal abundance between heterozygotes and homozygotes incorrect. The actual probability of inheritance is more complex, factoring in the rarity of the disease allele and the higher number of heterozygotes. Thus, the simplified probability of 75% mentioned is misleading and does not accurately reflect the genetic dynamics of Huntington's disease.
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If one of your parents has Huntington's disease, you have a 50% chance of getting the gene for the disease.

This IS wrong. This only holds true if one of your parents is HETEROZYGOUS dominant.

Hh x hh => 50% chance of offspring having Huntington's disease.

However, if one of your parents is HOMOZYGOUS DOMINANT ..

HH x hh => 100% chance of offspring having Huntington's diseases.

Simple Punnett squares will verify the above.

Therefore, the probability should be 75% if one parent has Huntington's disease. Am I right?
 
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Qube said:
This IS wrong. This only holds true if one of your parents is HETEROZYGOUS dominant.

Hh x hh => 50% chance of offspring having Huntington's disease.

However, if one of your parents is HOMOZYGOUS DOMINANT ..

HH x hh => 100% chance of offspring having Huntington's diseases.

Simple Punnett squares will verify the above.

Therefore, the probability should be 75% if one parent has Huntington's disease. Am I right?

I don't know what you are quoting or context, but I'd guess this is an approximation based on homozygous being rare in the population.

The dynamics of Huntingdon's is a bit more complex than just the inheritance of a stable chromosome, and was explained in a recent thread on PF.
 
You are making the faulty assumption that heterozygotes and homozygotes are equally abundant. In reality, the probability is 0.5p+(1-p), where p is the proportion of Huntington's patients who are heterozygous for the disease allele. As mentioned by epenguin, the disease allele is rare, so there are many more heterozygotes than homozygotes, and p~1.
 
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