Lim as x->a f(x) = L PROOF using epsilon and delta

[finishimx7]

Suppose lim_x->a f(x) = L does NOT equal 0.

Prove that there exists a (delta) d > 0 such that 0<|x-a|<d

which implies f(x) does NOT equal 0.


Does Anybody Know the Proof For This?

 

[mathman]

Your statement is incomplete.

 

[deluks917]

Make epsilon less = |L|.