Limit Calculator for \sqrt{x^{2}+5} and \sqrt{x^{2}+2} with x\rightarrow \infty

  • Thread starter Thread starter walker242
  • Start date Start date
  • Tags Tags
    Limit
walker242
Messages
12
Reaction score
0

Homework Statement


Calculate the limit of
<br /> \lim_{x\rightarrow \infty} \frac{\sqrt{x^{2}+5} - x}{\sqrt{x^{2}+2} - x}<br />

Homework Equations


-

The Attempt at a Solution


Neither multiplying with the conjugate nor trying to break out x helps me, as I'm left with "0/0" in those cases.
 
Physics news on Phys.org


do you know l'hopitals rule? could help here i think
 


While I do know l'Hopitals rule, we have not yet covered it in the course. The problem should be solved without using (sadly).
 


walker242 said:

Homework Statement


Calculate the limit of
<br /> \lim_{x\rightarrow \infty} \frac{\sqrt{x^{2}+5} - x}{\sqrt{x^{2}+2} - x}<br />

how about this, multiply by both conjugates of the numerator & denominator to get:

<br /> \lim_{x\rightarrow \infty} \frac{5 \sqrt{x^{2}+2} + x}{2 \sqrt{x^{2}+5} +x}<br />

already looking in better shape, as its not a difference term that is leading to the zero, which ws the tricky bit, so from here I'd try multiplying through by:

<br /> \lim_{x\rightarrow \infty} \frac{\frac{1}{x}}{\frac{1}{x}}<br />

this should change the terms containing x in the numerator & denominator from tending to infinity, to ones tending to zero...
 


lanedance said:
how about this, multiply by both conjugates of the numerator & denominator to get:

<br /> \lim_{x\rightarrow \infty} \frac{5 \sqrt{x^{2}+2} + x}{2 \sqrt{x^{2}+5} +x}<br />

already looking in better shape, as its not a difference term that is leading to the zero, which ws the tricky bit, so from here I'd try multiplying through by:

<br /> \lim_{x\rightarrow \infty} \frac{\frac{1}{x}}{\frac{1}{x}}<br />

this should change the terms containing x in the numerator & denominator from tending to infinity, to ones tending to zero...

\lim_{x\rightarrow \infty} \frac{5\sqrt{x^{2}+2} + x}{2\sqrt{x^{2}+5} +x} = \lim_{x\rightarrow\infty} = \frac{5}{2}\frac{x(\sqrt{1+\frac{2}{x}})+1}{x(\sqrt{1+\frac{5}{x}})+1} = \frac{5}{2}\cdot\frac{2}{2} = \frac{5}{2}<br /> <br />

Cheers!
 


walker242 said:
\lim_{x\rightarrow \infty} \frac{5\sqrt{x^{2}+2} + x}{2\sqrt{x^{2}+5} +x} =


\lim_{x\rightarrow\infty}\frac{5}{2}\cdot \lim_{x\rightarrow\infty}\frac{x\bigg( \sqrt{1+ \frac{2}{x^2}} + 1\bigg)}{x\bigg(\sqrt{1 + \frac{5}{x^2}}+1\bigg)} =


\frac{5}{2}\cdot\frac{2}{2} = \frac{5}{2}

There were some significant errors in this (highlighted in the

quote box) post from a user, that I felt one of the corrected

versions should be shown.
 


This thread is 2 years old. You've been here long enough to know not to necropost.
 
Back
Top