Limit of a function of more than one variable

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
mathe
Messages
3
Reaction score
0
Prove that
[tex]\lim_{x \to\0 ,y\rightarrow 0}(x+y)sin\frac{1}{x}sin\frac{1}{y}=0[/tex]
 
Physics news on Phys.org


tiny-tim said:
hi mathe! welcome to pf! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:

Here's what I've tried
\[|(x+y)sin\frac{1}{x}sin\frac{1}{y}|\leq |x+y|\rightarrow 0 (as x,y\rightarrow 0)\]
but it seems to me so simple and too obvious...so I'm not sure about the solution
 
hi mathe! :smile:

(you forgot to type "tex"! :wink:)
mathe said:
Here's what I've tried
[tex]\[|(x+y)sin\frac{1}{x}sin\frac{1}{y}|\leq |x+y|\rightarrow 0 (as x,y\rightarrow 0)\][/tex]
but it seems to me so simple and too obvious...so I'm not sure about the solution

looks fine to me :smile: