- #1
Kindayr
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my midterm is in 4 hours and this actually the only thing i need help with.
prove using squeeze theorem that lim(x-> +inf) (x^2 - [[x^2]])/x = 0
g(x)<=f(x)<=h(x) [squeeze theorem]
on the assignment i didn't know we had to use squeeze, so i just plugged in +inf and got 0, but we had to use squeeze. i wasn't there for his explanation of it.
all i need help with is setting up the inequality for the squeeze theorem and I'm fine, I'm just drawing blanks for all of this. help would be sooooo amazing. again, this is the only thing I'm confused on for my midterm.
Homework Statement
prove using squeeze theorem that lim(x-> +inf) (x^2 - [[x^2]])/x = 0
Homework Equations
g(x)<=f(x)<=h(x) [squeeze theorem]
The Attempt at a Solution
on the assignment i didn't know we had to use squeeze, so i just plugged in +inf and got 0, but we had to use squeeze. i wasn't there for his explanation of it.
all i need help with is setting up the inequality for the squeeze theorem and I'm fine, I'm just drawing blanks for all of this. help would be sooooo amazing. again, this is the only thing I'm confused on for my midterm.