Limit of Sequence: Finding the Limit of a Sequence (2)

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The limit of the sequence An = n^n / (n+3)^(n+1) is being discussed, with the correct answer being 0, contrary to one user's claim of 1. A key point raised is the incorrect application of logarithmic properties, specifically that ln(a/b) equals ln a - ln b, not ln a/ln b. Additionally, an alternative approach suggested involves factoring out n from the denominator to simplify the limit calculation. The discussion emphasizes the importance of proper mathematical techniques in finding limits of sequences.
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Homework Statement



Find the limit of this sequence

An =\frac{n^{n}}{(n+3)^{n+1}}

Homework Equations

The Attempt at a Solution



infinite_limit.jpg


The answer is 0 but my answer is 1

thank you
 
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Your first step is wrong.
\ln \frac{a}{b}≠\frac{\ln a}{\ln b}

The correct property is:
\ln \frac{a}{b}= ln a-\ln b

Anyways, instead of taking log on both the sides, you can factor out n from denominator.
 
Pranav-Arora said:
Anyways, instead of taking log on both the sides, you can factor out n from denominator.

Sorry I cannot see how n can factor out from denominator
 
like this ??

http://postimage.org/image/7cqb5oowp/ Thanks
 
Last edited by a moderator:
limit_2.jpg
 
What I actually meant was this:
\lim_{n→∞} \frac{1}{n+3} \left( \frac{1}{1+\frac{3}{n}} \right)^n
 
Thank you
 

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