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Limit tan(sqrt(x)) answer check please!

  1. Sep 28, 2009 #1
    limit tan(sqrt(x)) answer check please!:)

    1. The problem statement, all variables and given/known data
    tan(sqrt(x))
    locate discontinuities

    3. The attempt at a solution
    tan(sqrt(x))=
    sin(sqrt(x))/cos(sqrt(x))

    so x cannot= (pi/2)2 + (pi)n when n is an integer

    I am just wondering if this is correct
     
    Last edited: Sep 28, 2009
  2. jcsd
  3. Sep 28, 2009 #2

    Mark44

    Staff: Mentor

    Re: limit tan(sqrt(x)) answer check please!:)

    No.
    There are a couple of things to consider:
    1. the domain of sqrt(x)
    2. the domain of the tangent function.
    Changing tan(x) to sin(x)/cos(x) isn't any help, I don't believe.

    If we let y = sqrt(x), y will be in the domain of the tangent function provided that y = [itex]\pi/2 + k\pi[/itex]
    IOW, [itex]\sqrt{x} = \pi/2 + k\pi[/itex], where k is an integer.
    I believe you were on this track, but solved this equation incorrectly. Try again.
     
  4. Sep 28, 2009 #3
    Re: limit tan(sqrt(x)) answer check please!:)

    what does IOW mean? x must be greater then one and cannot equal ((pi/2 + (pi)n)^2 when n is a positive integer right?
     
  5. Sep 28, 2009 #4

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    Re: limit tan(sqrt(x)) answer check please!:)

    IOW means either 'In Other Words' or 'Isle of Wight'. Pick one. I just looked it up. Mark44 is saying tan(sqrt(x)) isn't defined if sqrt(x)=pi/2+k*pi where k is an integer. Solve for x. It's not quite what you said it was.
     
  6. Sep 28, 2009 #5
    Re: limit tan(sqrt(x)) answer check please!:)

    If I were to say tan(sqrt(x)) is not defined if x is less then zero or equal to (Pi/2+K*pi)^2 where k is an integer would that be correct?
     
  7. Sep 28, 2009 #6

    Dick

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    Science Advisor
    Homework Helper

    Re: limit tan(sqrt(x)) answer check please!:)

    Yes.
     
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