Limits of functions with more than one variable

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SUMMARY

The function f(x,y) = 2xy/(x^2+y^2) is continuous at every point except the origin (0,0). By substituting y=mx and m=tan(theta), it is demonstrated that the limit of f as (x,y) approaches (0,0) varies based on the angle of inclination, yielding values from -1 to 1. The derived expression Sin(2theta) confirms that the limit is dependent on the angle of approach, illustrating the function's behavior along linear paths towards the origin.

PREREQUISITES
  • Understanding of multivariable calculus
  • Familiarity with limits and continuity in functions of two variables
  • Knowledge of trigonometric identities, specifically Sin(2theta)
  • Ability to perform substitutions in mathematical expressions
NEXT STEPS
  • Study the concept of limits in multivariable functions
  • Explore the implications of continuity and discontinuity in calculus
  • Learn about polar coordinates and their application in evaluating limits
  • Investigate the behavior of functions along different curves approaching a point
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Students and educators in mathematics, particularly those focusing on calculus and analysis of multivariable functions, as well as anyone interested in understanding the limits of functions with multiple variables.

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Homework Statement



(Q) f(x,y) = 2xy/(x^2+y^2), (x,y) not = 0.
0 (x,y) = 0.
is continuous at every point except the origin.

(a) Substitute y=mx and then m=tan(theta) to show that f varies with the line's angle of inclination.

(b) Use the formula obtained in part (a) to show that the limit of f as (x,y) ---> (0,0) along the line y=mx varies from -1 to 1. depending on the angle of approach.

Homework Equations





The Attempt at a Solution



After doing all the substitutions, I get Sin(2theta). From that, it is clear that as the angle changes, so will the limit of f(x,y). Moreover, Sin(2theta) can only have values between -1 and 1. But, how does that mean that the limit of f as (x,y) ---> (0,0) along the line y=mx varies from -1 to 1. depending on the angle of approach.

Shouldn't it be "the limit of f as (x,y)---> (0,0) ALONG THE CURVE y=Sin(2theta)??
 
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You've already fixed the curve before you evaluated the limit.
You said y=mx, where m=tan(theta). So you're considering the value of f(x,y) for those points on that line and you find that the value doesn't depend on x and y at all, but has the constant value sin(2theta) along that line (minus the origin).
So clearly the limit along the line varies as you vary theta.
 
Thanks!

Thanks a lot for that little tid-bit! :smile:
 

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