Line integral around a circle in polar coordinates

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SUMMARY

The discussion centers on the evaluation of the line integral around a unit circle in polar coordinates, specifically addressing the integral \(\oint_{C}\mathrm{d}\vec{l}\). The user calculates the integral as \(\int_{0}^{2\pi}\hat{\phi}\mathrm{d}\phi = 2\pi\hat{\phi}\), which yields a non-zero result, contradicting the established fact that the integral over any closed curve should equal zero. The confusion arises from the interpretation of the line element \(\mathrm{d}\vec{l}\) in the azimuthal direction.

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JacobNielsen
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I know that \oint_{C}\mathrm{d}\vec{l} = 0, for any closed curve C.
But when i try to calculate the integral around the unit circle in polar coordinates, I get a result different from zero.

Here is my approach : \oint_{C}\mathrm{d}\vec{l} = \int_{0}^{2\pi}\hat{\phi}\mathrm{d}\phi = 2\pi\hat{\phi} \neq 0
Since the line element \mathrm{d}\vec{l}is pointing in the azimuthal direction.<br /> <br /> Where do I make a mistake?<br /> <br /> Thank you in advance.
 
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