Line segments problem with ratios.

  • Thread starter Thread starter bsodmike
  • Start date Start date
  • Tags Tags
    Line Ratios
AI Thread Summary
The discussion revolves around a geometry problem where the line AB intersects another line at point M, and the task is to find the coordinates of M and demonstrate that it divides AB in a 2:1 ratio. The equation of line AB is given as y=(2/3)x+4, and the provided solution for M is (3,6). Participants express concern that the problem is incomplete since the coordinates for points A and B are not provided, making it difficult to validate the ratio division. Suggestions are made to use Pythagorean principles to estimate points A and B, but this would lead to multiple possible solutions, highlighting the ambiguity of the question. Overall, the consensus is that the problem lacks clarity and specificity for a definitive solution.
bsodmike
Messages
82
Reaction score
0

Homework Statement



The line AB meets the line 3x+2y-21=0 at M. Find the coordinates of M and show that M divides AB in the ratio 2:1

Equation of AB is y=(2/3)x+4

Homework Equations



Given solution of M is (3,6).

The Attempt at a Solution



First solve for y such that y=-\dfrac{3}{2}x+\dfrac{21}{2}. Was thinking of equating the point-formula to this to find M, of course handling the ratio is an issue. Of course, the line M will have a gradient of m=2/3.

Help in advance is greatly appreciated!
 
Last edited:
Physics news on Phys.org
bsodmike said:

Homework Statement



The line AB meets the line 3x+2y-21=0 at M. Find the coordinates of M and show that M divides AB in the ratio 2:1

Equation of AB is y=(2/3)x+4
Are you sure this is the exact wording of the problem? AB would normally be the line segment from point A to point B. If you're not given at least one of the points A or B, I don't know how you're going to show that M divides AB in the specified ratio.
bsodmike said:

Homework Equations



Given solution of M is (3,6).

The Attempt at a Solution



First solve for y such that y=-\dfrac{3}{2}x+\dfrac{21}{2}. Was thinking of equating the point-formula to this to find M, of course handling the ratio is an issue. Of course, the line M will have a gradient of m=2/3.

Help in advance is greatly appreciated!
 
The problem description is incomplete. You must be given the coordinates for A and B.
 
Mark44 said:
Are you sure this is the exact wording of the problem?

According to my cousin it is. Her AS level teacher has posed this same question twice.

Mark44 said:
AB would normally be the line segment from point A to point B. If you're not given at least one of the points A or B, I don't know how you're going to show that M divides AB in the specified ratio.

Hmm that is what I thought as well. Just a thought though, couldn't one use Pythagoras to 'set' A' and B' about M with a ratio 2:1?

Of course, this would result in many answers as not only can one divide the line-segment as 2:1 or 1:2 about M but there is also no restriction on the particular lengths. Frankly, it does seem like an incomplete question as one would expect a singular solution; it is far too arbitrary, especially for AS level!

Thanks Mark and Symbolipoint for your time!
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top