Line that intersects and is perpendicular to another line

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SUMMARY

The discussion focuses on finding a line that intersects and is perpendicular to a given line defined by the parametric equations x = -1 + t, y = -2 + t, z = 1 + t. The direction vector of the given line is <1, 1, 1>. To find the required line through the point (4, 1, -1), the dot product of the direction vector and the vector PQ = <(x-4), (y-1), (z+1)> must equal zero. The user is advised to substitute the parametric equations into the dot product equation to solve for the parameter t.

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  • Familiarity with parametric equations of lines
  • Knowledge of coordinate geometry in three dimensions
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Homework Statement


Find the line through (4, 1, -1) that intersects and is perpendicular to the line
{
x = -1 +t
y = -2 + t
z = 1 +t
}

Homework Equations


if they are perpendicular, the dot product of two vectors has to be zero.
The book gives me another hint, if (x, y, z) is the point of intersection, find it's coordinates.

The Attempt at a Solution


The direction vector for the line l is <1, 1, 1>
The vector for the line I'm trying to find is PQ = <(x-4), (y-1), (z+1)>
if i do the dot product, i get
(x-4)1 + (y-1)1 + (z+1)1 = 0.

at this point, the only x, y and z i can think of to make the whole thing zero are (4,1,-1)...

i am really confused on what i should do next.
 
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Substitute the parametric form x=t-1 etc into the dot product equation. Find t.
 

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