Lineal Transformation basis change

[SqueeSpleen]

Find


http://imageshack.us/a/img35/1637/lineal2.gif


http://imageshack.us/a/img210/1370/lineal1.gif




C^3 is the canonical base of ℝ^3, C^2 is the canonical base of ℝ^2

I tried:
http://imageshack.us/a/img822/6274/lineal3.gif


But I'm not sure if this is right, I made a mistake here or I'm not checking this right.
I think, if this is well done I have to have the same answer when putting the vectors of canonical basis (1,0,0), (0,1,0), (0,0,1), the result in canonical ℝ^2 has to be the same result that I got if I use (1,0,1), (1,1,1), (1,0,0) in ℝ^2 using B'

I hope I was clear enough, I don't speak English very well.

 

[camjohn]

This isn't pre-calculus. You should move this into the "calculus and beyond," section.

 

[micromass]

This isn't pre-calculus. You should move this into the "calculus and beyond," section.

Please report such things instead of replying in the thread.

 

[SqueeSpleen]

I figured out what was wrong.
I knew:
http://imageshack.us/a/img23/6742/transformationq.png
So I had to do:
http://imageshack.us/a/img594/6012/lineartransformation.gif

Instead of:
http://imageshack.us/a/img822/6274/lineal3.gif Offtopic: What's Calculus and Beyond? I only know how to classify Calculus :p, I didn't know where to put my Linear Algebra doubts.