Linear Algebra- Diagonal Matrix

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SUMMARY

The discussion centers on the properties of diagonal matrices, specifically an n x n diagonal matrix D with diagonal entries of 0 or 1. It is established that D is idempotent, meaning D² = D. Additionally, if X is a nonsingular matrix and A = XD(X)⁻¹, then A is also idempotent. The participants clarify that the product of two matrices (AB)² does not equal A²B² or B²A², but is simply ABAB.

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  • Understanding of diagonal matrices
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  • Familiarity with idempotent matrices
  • Basic linear algebra concepts
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  • Learn about nonsingular matrices and their implications
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Students and educators in linear algebra, mathematicians focusing on matrix theory, and anyone seeking to deepen their understanding of matrix properties and operations.

Roni1985
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Homework Statement



Let D be an n x n diagonal matrix whose diagonal entries are either 0 or 1

a) Show that D is idempotent

b) Show that if X is a nonsingular matrix and A=XD(X)-1 , then A is idempotent

Homework Equations


The Attempt at a Solution



a) I tried it, and it works for a specific matrix, say 3x3... but I don't know if it's really a proof.
I need to show that

D2=D

b) I solved this part

Also,
is (AB)2= A2*B2
or
(AB)2=B2*A2
?
 
Last edited:
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You just need to make up some notation. Let diag(a1,a2,...an) be the matrix whose diagonal entries are a1, a2... Now what diag(a1,a2,...an)*diag(b1,b2,...bn)? (AB)^2 generally isn't equal to either A^2*B^2 or B^2*A^2. It's just ABAB.
 
Dick said:
You just need to make up some notation. Let diag(a1,a2,...an) be the matrix whose diagonal entries are a1, a2... Now what diag(a1,a2,...an)*diag(b1,b2,...bn)? (AB)^2 generally isn't equal to either A^2*B^2 or B^2*A^2. It's just ABAB.

oh, right , it works ...
thanks a lot for the help ...
 

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