Linear algebra: Finding a linear system with a subspace as solution set

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SUMMARY

The discussion focuses on finding a homogeneous linear system with a solution set defined by the subspace generated by the vectors (2,6,2) and (6,2,2) in R^3. It is established that the subspace is two-dimensional, necessitating a system with three variables and two equations. The equations can be represented as ax + by + cz = P and dx + ey + fz = Q, leading to a set of four equations to solve for eight variables. The solution involves expressing four variables in terms of the remaining four, allowing for flexibility in choosing values.

PREREQUISITES
  • Understanding of R^3 vector spaces
  • Knowledge of homogeneous linear systems
  • Familiarity with solving systems of equations
  • Basic linear algebra concepts, including subspaces and dimensions
NEXT STEPS
  • Study the properties of homogeneous linear systems in linear algebra
  • Learn how to derive equations from vector subspaces
  • Explore methods for solving systems of equations with multiple variables
  • Investigate the implications of dimensionality in vector spaces
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Students of linear algebra, educators teaching vector spaces, and anyone interested in solving linear systems involving subspaces in R^3.

sphlanx
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Homework Statement



We are given a subspace of R^3 that is produced by the elements: (2,6,2) abd (6,2,2). We are asked to find (if any) a homogeneous linear system that has this subspace as solution set.



Homework Equations





The Attempt at a Solution



1)The subspace is 2 dimensional so the solution set must have 2 parameters. Also, given the elements that produce the subspace, i guess we want a system with 3 variables and 2 equations.

No clue after that :S
 
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sphlanx said:

Homework Statement



We are given a subspace of R^3 that is produced by the elements: (2,6,2) abd (6,2,2). We are asked to find (if any) a homogeneous linear system that has this subspace as solution set.



Homework Equations





The Attempt at a Solution



1)The subspace is 2 dimensional so the solution set must have 2 parameters. Also, given the elements that produce the subspace, i guess we want a system with 3 variables and 2 equations.

No clue after that :S
Yes, that's right. You want to equations, say ax+ by+ cz= P and dx+ ey+ fz= Q that are both satisfied by (2,6,2) and (6,2,2). That is, you must have the four equations 2a+ 6b+ 2c= P, 2d+ 6e+ 2f= Q, 6a+ 2b+ 2c= P, and 6d+ 2e+ 2f= Q. That gives you four equations to solve for 8 numbers, but, of course there are many sets of equations that will satisfy this problem. Solve for four of the variables in terms of the other four, then choose whatever numbers you please for those four.
 

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