Linear Algebra / Geomtric Multiplicity

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Homework Help Overview

The discussion revolves around a 2x2 matrix A and involves finding its eigenvalues, algebraic multiplicities, and geometric multiplicities. Participants are exploring concepts related to linear algebra, specifically eigenvalues and eigenvectors.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the geometric multiplicity of the eigenvalue found and questions whether their reasoning about the kernel dimension is correct. Other participants confirm the eigenvalue and its multiplicity but do not provide further solutions.

Discussion Status

Participants are actively discussing the eigenvalue and its corresponding eigenvector. Some guidance has been offered regarding the relationship between algebraic and geometric multiplicities, but there is no explicit consensus on the next steps for finding additional eigenvectors or the Jordan form.

Contextual Notes

There is mention of needing to find a second eigenvector and the constraints of the problem, including the requirement to express the matrix in Jordan canonical form. The original poster is unsure about the choice of eigenvector and the implications of their selection.

Wildcat
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Homework Statement


Let A = a 2x2 matrix row 1 [3/2 ½ ] row 2 [-½ ½]
a) Find the eigenvalue(s) of A
b) Find the algebraic multiplicity of each eigenvalue.
c)Find the geometric multiplicity of each eigenvalue.



Homework Equations





The Attempt at a Solution


I found the eigenvalue to be 1 with an algebraic multiplicity of 2.
I'm not sure about the geometric multiplicity. I think it is 1.
When I look at the dim(ker(A-1I)) I get ½x1 + ½x2=0 which I think means you have 1 degree of freedom therefore the geometric multiplicity is 1.
Can someone tell me if I'm doing this right?
 
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That's right. 1 is a double eigenvalue but it only corresponds to a single eigenvector.
 
Dick said:
That's right. 1 is a double eigenvalue but it only corresponds to a single eigenvector.

Thanks! I also have to find P and J such that A=PJP^-1 where J is the Jordan canonical form of A, but I'm not finished with that.
 
Wildcat said:
Thanks! I also have to find P and J such that A=PJP^-1 where J is the Jordan canonical form of A, but I'm not finished with that.

I know I need to find the eigenvector corresponding to the eigenvalue 1, I found it to be
[1 -1] but I need another one. Do I choose one where (A-1I)v‡0, can I choose [1 0] for the other??
 
Wildcat said:
I know I need to find the eigenvector corresponding to the eigenvalue 1, I found it to be
[1 -1] but I need another one. Do I choose one where (A-1I)v‡0, can I choose [1 0] for the other??

if I can do that, I get P=[1 1] [-1 0] J=[1 ½] [0 1] P^-1=[0 -1] [1 1] (these are 2x2 matrices)


which does = A [3/2 ½] [-½ ½] ?
 

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