Linear Algebra Homework: Matrix \Gamma^{\mu}p_{\mu} Rank

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The discussion focuses on determining the rank of the matrix \Gamma^{\mu}p_{\mu} in the context of space-time supersymmetry and the equations of motion. The matrix is represented in a simplified 3x3 form, leading to three equations derived from the product with the anti-commuting spinor \dot{\theta}. The key point is that the equations are linearly independent, suggesting that the rank of the matrix can be at most 1, given that there are 3 equations and 2 constraints. The discussion emphasizes the need for a mathematical expression to clarify this relationship. Understanding these concepts is crucial for solving problems related to matrix ranks in string theory.
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Homework Statement


Ok, it seems I need to refresh my linear algebra a bit. In the string theory exams, we had a part about space-time supersymmetry of the superparticle. On of the questions was this:

Argue that the matrix \Gamma^{\mu}p_{\mu} can have at most half maximal rank upon imposing the equations of motion.

(Recall that any matrix can be brought to Jordan normal form, meaning that it is diagonal with at most 1s in places right above the diagonal entries.

Homework Equations


Equations of Motion (the relevant ones):
\Gamma^{\mu} p_{\mu} \dot{\theta}=0, where \dot{\theta}(\tau) is an anti-commuting spinor in space-time and has 32 components (we're working in 10 dimensions.


The Attempt at a Solution



I write \Gamma^{\mu}p_{\mu} \dot{\theta}=0 as (I use 3x3 for simplicity)

\begin{pmatrix}<br /> a &amp; 1 &amp; 0\\ <br /> 0 &amp; b &amp; 1\\ <br /> 0 &amp; 0 &amp; c<br /> \end{pmatrix}<br /> \begin{pmatrix}<br /> \dot{\theta_0}\\ <br /> \dot{\theta_1}\\ <br /> \dot{\theta_2}<br /> \end{pmatrix}=0

From this I get 3 equations, but I'm not really sure how they affect the rank.
 
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I think it has something to do with the fact that the equations are linearly independent and so the rank of \Gamma^{\mu}p_{\mu} can be at most 3-2=1, but I'm not sure how to express this mathematically. Any help would be appreciated.
 

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