SticksandStones said:
Homework Statement
Given:
[tex]v_1 = \left(\begin{array}{cc}1\\-5\\-3\end{array}\right)<br />
<br />
v_2 = \left(\begin{array}{cc}-2\\10\\6\end{array}\right)<br />
<br />
v_3 = \left(\begin{array}{cc}2\\-9\\h\end{array}\right)<br />
[/tex]
For what value of h is [tex]v_3[/tex] in Span{[tex]v_1, v_2[/tex]} and for what value of h is {[tex]v_1,v_2,v_3[/tex]} linearly dependent?
Homework Equations
The Attempt at a Solution
If my understanding is correct, a vector is in a span of another set of vectors if all vectors are in the same plane?
You understanding is not quite correct. A vector is in a span of another set of vectors if it can be written as a linear combination of the vectors in the set. The span of the set of vectors is a plane only if there are exactly
two independent vectors in the set. That is
not true in this problem!
If so then my guess is h would have to be a multiple of -3.
The linear dependence part of the question is getting me though. I was under the impression that all three vectors would have to be multiples of each other for it to be linearly dependent?
Are these really the problem you were given? Have you copied the vectors correctly? Notice that -2v
1= v
2. The span of these two vectors has dimension 1, not 2. v
3 will be in their span only if it also is a multiple of either v
1 or v
2. The first component of v
3, 2, is 2 times the first component of v
1 (and -1 times the first component of v
2) but the second component of v
3 is -9 which is
not 2 times the second component of v
1 (and
not -1 times the second component of v
2).
v
3 while
not be in the span of v
1 and v
2 for
any value of h.
(
If the second component of v
3 were -10, then v
3 would be in the span of v
1 and v
2 for h= -6.)