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Linear algebra, parametric equation, intersectin of line

  1. Mar 5, 2009 #1
    1. The problem statement, all variables and given/known data

    Two equations for two planes in 3-D
    2x+y-2z=1
    x-2y+z=-3
    Find the parametric equation for the line of intersection of the two planes by solving these two equations togeather.

    3. The attempt at a solution

    Gauss Jordan gives:
    1 0 -3/5 -1/5
    0 1 -4/5 7/5

    if z=t
    x=3/5t-1/5
    y=4/5t+7/5

    I don´t know how to finish the problem.
     
    Last edited: Mar 5, 2009
  2. jcsd
  3. Mar 5, 2009 #2
    You have already solved the problem!

    x=3/5t-1/5
    y=4/5t+7/5
    z=t

    is the parametric equation for the intersection.
     
    Last edited: Mar 5, 2009
  4. Mar 5, 2009 #3

    Dick

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    You are already finished. z=t, x=(3/5)t-1/5 and y=(4/5)t+7/5 is the intersection line in parametric form. Are you supposed to express it in vector form or something?
     
  5. Mar 5, 2009 #4
    really? I thought this was only the parametric equation and I had to find some special line of intersection as well.
     
  6. Mar 5, 2009 #5

    Dick

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    Nah. The problem says find the line that is the intersection of the two planes. No line intersection involved.
     
  7. Mar 5, 2009 #6
    okey thanks for that
     
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