Linear algebra, point of intersection

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Homework Help Overview

The discussion revolves around finding the point of intersection between a line defined parametrically and a plane represented by a linear equation. The line is given by the equations x=3+t, y=2-4t, and z=-5+11t, while the plane is described by the equation 12x+10y-4z=48.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of the intersection between the line and the plane, questioning the correct form of the plane's equation. There is an exploration of substituting the line's parametric equations into the plane's equation to find the intersection point.

Discussion Status

Some participants have provided guidance on how to approach the problem, suggesting substitution of the line's equations into the plane's equation. There is a recognition of differing interpretations regarding the plane's equation, with some participants noting the implications of the constants involved.

Contextual Notes

Participants express varying levels of familiarity with solving systems of linear equations, with some indicating they are beginners. There is mention of a specific value related to the plane's equation that may influence the discussion.

cleopatra
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Homework Statement


1) x=3+t
y=2-4t
z=-5+11t

2)12x+10y-4z

Find the point where these two lines intersect.


please help!
 
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I mean, where the line in 1 and plan in 2 intersect
 
cleopatra said:
1) x=3+t
y=2-4t
z=-5+11t

2)12x+10y-4z

Do you mean 12x+10y-4z=0?
Also, please show that you have https://www.physicsforums.com/showthread.php?t=94383".
 
Last edited by a moderator:
=48

but I don´t think that matters
 
cleopatra said:
=48

but I don´t think that matters

It does matter. The equation 12x+10y-4z=48 defines a different (but parallel) plane then the equation 12x+10y-4z=0. For example the second one passes through the origin while the first does not (to see this, just check if x=0,y=0,z=0 satisfies the equation).
 
okey thanks

but do you know how to solve it?
 
cleopatra said:
okey thanks

but do you know how to solve it?

This is a system of linear equations (4 equations, 4 unknowns). I am almost sure you have solved systems of linear equations before, for example when intersecting two lines in the plane:

2x+y=1
x-3y=0

How did you do that? Hint: Substitution. Your problem can be solved in a similar way.
 
I really haven´t solved anything like this. I´m a beginner.
I just really need a good teacher to show me how to do this.
Can you? Or if you can´t solve it, can anybody else?
And, the answer of the plane is =46, not 48.
 
you have an equation for a plane

ax + by + cz = d
a,b,c,d constants

and a line (x(t),y(t),z(t))

what happens when we are on both the plane & line? bothe equations will be solved

substitute your line components (x(t),y(t),z(t)) into the equation of the plane & solve for t

this give the point on the line in terms on twhere the plane & line intersect
 
  • #10
Put your expressions for x, y and z in terms of t into the equation of the plane. Then solve for t.
 
  • #11
Anyone who can show me some equations?
 

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