Linear algebra proof with annihilator

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ptolema
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Homework Statement



V is a finite-dimensional vector space over F.
For subspaces W1 and W2 of V, prove that
Equation: W1 = W2 if and only if W1^0 = W2^0, where W^0 denotes the annihilator of the subspace W.


Homework Equations



V* is dual space of V, defined V*=the set of all linear functionals

For every subset S of V, define annihilator
Set definition: S0 equals the set of all f in V* such that f(x) = 0 for all x in S, where V* is the dual space of V.


Set definition: W1 superscript 0 equals the set of all f in V* such that f(x) = 0 for all x in W1.

Set definition: W2 superscript zero equals the set of all f in V* such that f(x) = 0 for all x in W2, where V* is the dual space of V.


The Attempt at a Solution


I'm not really sure where to start. I proved in a previous part of the problem that the annihilator is a subspace of V*. I tried to argue that for two subspaces of a vector space, one of the subspaces is a subset of the other, but I don't know if that's even a valid theorem. Could someone shed some light on this?
 
Just use the basics. You have to show [itex]W_1=W_2 \Leftrightarrow W_1^0=W_2^0[/itex]

So start by showing [itex]W_1=W_2 \Rightarrow W_1^0=W_2^0[/itex] which looks to be trivial. So what about the other way: [itex]W_1^0=W_2^0\Rightarrow W_1=W_2[/itex]

If W1 ≠ W2 then ...
 
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