Linear Algebra: Vector Spaces; Dependent/Independent

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The discussion focuses on determining the linear dependence or independence of the set of functions {cos^2(x), sin^2(x), sin(2x)}. To prove independence, one must show that the equation a*sin^2(x) + b*cos^2(x) + c*sin(2x) = 0 has only the trivial solution where a = b = c = 0. Participants suggest using relationships between the functions, such as the identity sin^2(x) + cos^2(x) = 1, to aid in the proof. The challenge lies in translating these functions into a matrix form or finding linear combinations that demonstrate their independence. Ultimately, the goal is to establish that none of the functions can be expressed as a linear combination of the others.
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Decide if the indicated set of functions are independent or dependent, and prove your answer.

<br /> \left\{cos^2(x),sin^2(x),sin(2x)\right\}<br />

This linear algebra course is killing me. It's much more abstract than I thought it would be. I realize this problem isn't exactly that, but I am so overwhelmingly frustrated with this class.

Dependence/Indepence is determined if one of the vectors is/is not the zero vector. But for functions how do I interpret this? Do I set it up like an equation and set it to the zero vector? AAAHHHH! So. Completely. Lost. I've read this section twice now and I feel I have nothing to show for it.
 
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You need to determine whether:

asin2(x) + bcos2(x) +csin(2x) = 0

has any solution except a=b=c=0.

Basically can you write any of the three as linear cominqtions of the others. Do you know any realtions between sin2, cos2 and sin(2x)?
 
I realize that I can't do that, but how do I prove it? I was thinking about constructing a matrix but that seems ridiculous.
 
span(u,v) = span(u+v,u-v)

You can replace sin^2 and cos^2 with sin^2 + cos^2 and sin^2 -cos^2. Can you prove the resulting 3 functions are independent.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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