Linear approximation question of ##xy−5y^2##

A330NEO
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First, I already know that when we have to do linear approximation of ##f(x, y)## if ##\Delta z = f_{x}(a, b)\Delta x + f_{y}(a, b)\Delta y + \epsilon_{1}\Delta x + \epsilon_{2}\Delta y ##. and ##\epsilon_{1}## and ##\epsilon_{2}## approaches to nought wneh ##(\Delta x, \Delta y)## approaches zero. But how can I find appropriate value of ##\epsilon_{1}## and ##\epsilon_{2}##? in this question for example, epsilons of ##z = f(x, y) = xy-5y^2##?
 
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A330NEO said:
First, I already know that when we have to do linear approximation of ##f(x, y)## if ##\Delta z = f_{x}(a, b)\Delta x + f_{y}(a, b)\Delta y + \epsilon_{1}\Delta x + \epsilon_{2}\Delta y ##. and ##\epsilon_{1}## and ##\epsilon_{2}## approaches to nought wneh ##(\Delta x, \Delta y)## approaches zero. But how can I find appropriate value of ##\epsilon_{1}## and ##\epsilon_{2}##? in this question for example, epsilons of ##z = f(x, y) = xy-5y^2##?
First off, do not delete the three parts of the template. They are there for a reason.

The formula you show for ##\Delta z## gives the exact change in z (or in your case, f). What you're after is a linear approximation, so you can ignore the two terms with ##\epsilon##.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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