- #1
Roodles01
- 128
- 0
I have a number with which I must use rules of congruence to find the remainder.
rules I must apply are;
split every 3 digits, starting from the right,
find the remainder of each 3 digit number on division by 7
form alternating sum of these remainders.
Thisnumber should be congruent to a modulo 7
the number is 2468135711201104
number 2 468 135 711 201 104
remain 2 6 2 4 5 6
Alternating sum 6-5+4-2+6-2 = 7
So a = 7 (mod 7)
I have gone through this several times with the same result
Would this be right?
Dividing through by 7 only to have a remainder of 7 seems a bit odd!
rules I must apply are;
split every 3 digits, starting from the right,
find the remainder of each 3 digit number on division by 7
form alternating sum of these remainders.
Thisnumber should be congruent to a modulo 7
the number is 2468135711201104
number 2 468 135 711 201 104
remain 2 6 2 4 5 6
Alternating sum 6-5+4-2+6-2 = 7
So a = 7 (mod 7)
I have gone through this several times with the same result
Would this be right?
Dividing through by 7 only to have a remainder of 7 seems a bit odd!