Linear differential equation problem

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Homework Help Overview

The discussion revolves around a linear differential equation of the first order, specifically the equation dy/dx + 2y = xe^x. Participants are exploring the methods for solving this type of equation, particularly focusing on the use of integrating factors.

Discussion Character

  • Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to relate the given equation to previously learned methods for solving differential equations, expressing uncertainty about its format. Some participants inquire about the specifics of the equation's structure and the conditions under which it can be solved.

Discussion Status

The discussion is active, with participants questioning the original poster's understanding of the equation's format and encouraging them to articulate their knowledge of solving linear differential equations. There is an exploration of the characteristics of the functions involved in the equation.

Contextual Notes

Participants note that the functions p(x) and q(x) in the general form of the equation can be constant functions, which may influence the approach to solving the problem.

tunabeast
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Homework Statement


[tex]\ \frac{dy}{dx} + 2y = xe^x[/tex]



Homework Equations





The Attempt at a Solution


I'v only ever solved differential equations where values can be separated easily, i understand i may have to use something called the integrating factor but this does not seem to fit the formula layout of

img1.gif
 
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The equation you presented:

[tex]\frac{dy}{dx}+p(x)\cdot y=q(x)[/tex]

is a linear differential equation of the first order. This is the next type you learn after the ones you can separate immediately. It has a general solution. What is your knowledge on the ways for solving these? You should have some idea about this, can you show an attempt of solving it?
 
tunabeast said:
[tex]\ \frac{dy}{dx} + 2y = xe^x[/tex]
... does not seem to fit the formula layout of

img1.gif
Why not? What doesn't match?
 
Remember that p(x) and q(x) can be 'constant functions'.
 

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