Linear Force to Torque Conversion

[unirobotics]

 

[jrmichler]

Physics answer: Torque is force times radius, so 4 tons X 20 mm. Then you need to put that into usable units, such as foot-lbs or Newton-meters. Be sure to use the gear pitch diameter, not the outside diameter.

More realistic answer: 4 tons will shear off the teeth of any normal 40 mm diameter gear, so zero torque.

 

[unirobotics]

Thank you for your reply.
Actually the gear and rack is hardened Hadox material and it is currently working in a machine. This gear can take up to 10 ton pressure (;-)

 

[unirobotics]

So what is the actual answer in Newtons?

 

[jbriggs444]

So what is the actual answer in Newtons?

Undefined. Torque is not measured in Newtons.

4 tons of force is about 35000 Newtons.
20 mm of radius is 0.02 meters.

Multiply them together and you have 35000 $\times$ 0.02 = 700 Newton-meters.

 

[unirobotics]

Undefined. Torque is not measured in Newtons.

No, torques IS measured in Newtons.

 

[jbriggs444]

No, torques IS measured in Newtons.

No, torque IS NOT measured in Newtons.

 

[unirobotics]

Newton Meters

 

[unirobotics]

I did not expect anyone to misunderstand. Actual NM is the abrv. But what is the answer, instead of haggling about a term

 

[jbriggs444]

I did not expect anyone to misunderstand. Actual NM is the abrv. But what is the answer, instead of haggling about a term

See the edit I'd already added to #5 above.

 

[vanhees71]

It's Newton times meter, i.e., Nm.

The torque relative to the origin of the frame of reference is $\vec{\tau}=\vec{r} \times \vec{F}$.

 

[unirobotics]

Ok, apologies. However, the problem is does the torque not vary with the input linear speed? The 35,000 Newtons are moving at 200mm per minute. What happens if it moves say 200mm per 20 seconds?

 

[jbriggs444]

Ok, apologies. However, the problem is does the torque not vary with the input linear speed? The 35,000 Newtons are moving at 200mm per minute. What happens if it moves say 200mm per 20 seconds?

No. Torque does not vary with input linear speed.

The power delivered by the torque does vary proportionally to input linear speed. You could compute that based on linear speed times linear force. Or as angular velocity times torque.

For force in Newtons and velocity in meters per second, the resulting power in Watts is simply force times [parallel] velocity.

For torque in Newton-meters and angular velocity in radians per second, the resulting power in Watts is simply torque times [aligned] angular velocity.

 

[unirobotics]

Thank you for your answer. It helped a great deal. Instead of posting a new question could I perhaps procure help in this:
what is the torque generated by an input shaft turning at 2000 RPM with an input NM torque of 0.32NM?

 

[unirobotics]

the shaft is 25mm Dia

 

[jbriggs444]

Thank you for your answer. It helped a great deal. Instead of posting a new question could I perhaps procure help in this:
what is the torque generated by an input shaft turning at 2000 RPM with an input NM torque of 0.32NM?

0.32 Nm. Barring any frictional resistance, the torque you can draw off from a shaft matches, on average, the torque you put in.

The torque delivered to the baler matches the torque delivered by the PTO on the tractor.

Note case sensitivity in unit abbreviations.

 

[A.T.]

Actual NM is the abrv.

NM : Nautical mile
Nm : Newton meter