Linear transformation across a line

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SUMMARY

The discussion focuses on the composition of two linear transformations, T1 and T2, which are reflections about the lines -4x - 1y = 0 and 4x - 5y = 0, respectively. The standard matrix for the composition T1 ∘ T2 is calculated as \begin{pmatrix} \frac{-455}{697} & \frac{-528}{697}\\ \frac{-455}{697} & \frac{-455}{697}\end{pmatrix}. The challenge lies in determining the equivalent counterclockwise rotation angle in radians resulting from this transformation.

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Using linear transformation reflection to find rotation

Homework Statement


Let T1 be the reflection about the line −4x−1y=0 and T2 be the reflection about the line 4x−5y=0 in the euclidean plane.

The standard matrix of T1 \circ T2 is what?

Thus T1 \circ T2 is a counterclockwise rotation about the origin by an angle of how many radians?


Homework Equations



\frac{1}{1+m^2}\begin{pmatrix}<br /> 1-m^2 &amp; 2m\\<br /> 2m &amp; m^2-1<br /> \end{pmatrix}


The Attempt at a Solution



I've used the relevant equation above and found that T1 \circ T2 = \begin{pmatrix}<br /> \frac{-455}{697} &amp; \frac{-528}{697}\\<br /> \frac{-455}{697} &amp; \frac{-455}{697}\end{pmatrix} and had this verified, but I have no idea how to relate this into an amount of radians rotated.
 
Last edited:
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hi 1up20x6! :smile:

should be \begin{pmatrix}<br /> \cos &amp; \sin\\<br /> -\sin &amp; \cos\end{pmatrix} :wink:
 

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