Linear Transformation Question: Solving for Im(T) in R^4 Dimension Space

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SUMMARY

The discussion focuses on solving for the image of a linear transformation in a four-dimensional space (R^4). Given the dimensions, the kernel of the transformation has a dimension of 2, leading to the conclusion that the image also has a dimension of 2, as per the theorem stating that dim(V) = dim(Ker(T)) + dim(Im(T)). To find the specific linear transformation, participants suggest representing it as a 4x4 matrix, which introduces 16 unknowns and 8 equations derived from the kernel condition Ax=0. The discussion also proposes exploring the concept of a projection matrix to simplify the transformation.

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  • Concept of projection matrices in vector spaces
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I need help with question from homework in linear algebra.

This question (linear transformation):
http://i43.tinypic.com/15reiic.gif

According to theorem dimensions:
dim(V) = dim(Ker(T)) + dim(Im(T)).

dim(Ker(T))=2.
dim(V) in R^4, meaning =4.

We can therefore conclude that dim(Im(T))=2.
But how can find this specific linear transformation?

Please help me to solve this problem.
Thanks.
 
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So let's write the transform as a 4x4 matrix A, giving 16 unknowns.

Now you you know Ax=0 for, x in the kernal. This gives you 8 equations, and is equivalent to mappint the plane contain the 2 kernal vectors to zero.

Clearly you still have more unknowns, so you will need to make some assumptions.

One of the simpler ones, might be to try and find the "projection matrix" which maps components in the kernal plane to zero, but leaves components perpindicular to that plane unchanged
 

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