Is L(x,y) a Linear Transformation?

AI Thread Summary
The discussion focuses on determining whether the function L(x,y) = (x+1, y, x+y) qualifies as a linear transformation. To establish this, it must satisfy the condition L(u+v) = L(u) + L(v). The user initially struggles with finding L(u+v) and calculating L(u) + L(v), leading to confusion over the transformation's definition. After clarification, it becomes evident that L(x+x', y+y') results in different outputs than L(u) + L(v), confirming that L is not a linear transformation. The conversation concludes with the user expressing understanding of the concept.
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[SOLVED] Linear Transformation

Homework Statement


Determine if this is a linear transformation:

L(x,y) = (x+1, y, x+y)


Homework Equations



This is just one, but I have no clue as to how to even begin. I've been to lecture and read the book over and over again, but i was not given any relevant examples. Could someone please walk me through this? I know that to show it is a linear transformation, i must show that L(u+v) = L(u) + L(v), but i can't seem to find L(u+v)


The Attempt at a Solution



u =
[x
y]

v =
[x'
y']

L(u) + L(v) =
x + x' + 2
y + y'
x + y + x' +y'

I'm not even sure that is correct, but if it is, how does one find L(u+v)? Additionally, the fact that it is a transformation from R^2 => R^3 is throwing me off
 
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The domain is R^2, they mean that (x,y)+(x',y') should be defined by (x+x',y+y'). What's L of that?
 
would L(x+x', y+y') = x+x'+2 ?
y+y'
x+1+y

It's probably extremely obvious, but i still don't understand.
 
L(x+x',y+y') would be (x+x'+1,y+y',x+x'+y+y'). Look at the definition. Substitute x+x' -> x and y+y' ->y. Notice that's different from what you found for L(u)+L(v).
 
ah that makes sense! I think i understand now.Thx for the help!
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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