Linear Transformations, Span, and Independence

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For a linear transformation T: Rn -> Rm represented by an m x n matrix A, it is established that if the columns of A span Rm, then T is onto. Conversely, if the columns of A are linearly independent, T is one-to-one, as demonstrated by the implication that T(v1) = T(v2) leads to v1 = v2. If m > n, T cannot be onto since the maximum dimension of the image is limited by n. Additionally, if the columns are independent, T(Rn) forms an n-dimensional subspace of Rm. Understanding these properties is crucial for grasping linear transformations in linear algebra.
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Is there a linear algebra theorem or fact that says something like

For a linear transformation T:Rn -> Rm and its standard m x n matrix A:
(a) If the columns of A span Rn the transformation is onto.
(b) If the columns of A are linearly independent the transformation is one-to-one.

Is this correct? I can't find it anywhere in my textbook but it may have been mentioned in lecture. Any insight would be appreciated.
 
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If m>n, then can T be onto? If the colomns are independent, T(Rn) will be an n-dimensional subspace of Rm.

b) is true, as you can easily prove yourself. Show that T(v1)=T(v2) implies that v1=v2.
Hint: If you column-vectors are independent you can use them as a basis.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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