MHB Lisa's question at Yahoo Answers (Matrix of a linear map)

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The discussion revolves around finding the matrix A of a linear transformation T defined by T(f(t)) = f''(t) + 3f'(t) + 4f(t) for the space spanned by cos(t) and sin(t). The transformation is applied to both basis functions, yielding T(cos(t)) = 3cos(t) - 3sin(t) and T(sin(t)) = 3cos(t) + 3sin(t). By transposing the coefficients from these results, the matrix A is determined to be [[3, 3], [-3, 3]]. Participants are encouraged to ask further questions in the Linear and Abstract Algebra section. This concise approach aids in understanding linear transformations in the context of trigonometric functions.
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Here is the question:

Let V be the space spanned by the two functions cos(t) and sin(t). Find the matrix A of the linear transformation T(f(t)) = f''(t)+3f'(t)+4f(t) from V into itself with respect to the basis {cos(t),sin(t)}.

Here is a link to the question:

Linear Algebra Problem *Help Please*? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
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Re: Lisa 's question at Yahoo! Answers (Matrix of a linear map)

Hello Lisa, we have: $$T(\cos t)=(\cos t)''+3(\cos t)'+4\cos t=-\cos t-3\sin t+4\cos t=3\cos t-3\sin t\\T(\sin t)=(\sin t)''+3(\sin t)'+4\sin t=-\sin t+3\cos t+4\sin t=3\cos t+3\sin t$$ Transposing coefficients: $$A=\begin{bmatrix}{3}&{3}\\{-3}&{3}\end{bmatrix}$$
If you have further questions, you can post them in the Linear and Abstract Algebra section.
 
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