- #1
Philosophaie
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I would like a list of ways highly accurate to solve the equation:
E - e * sin(E) = M
I can solve this with the Newton Method:
M = 2*pi/3
e = 0.002
E = pi
d = 0.01
Do While SQRT(d^2) > 0.000001
d= (E - e * sin(E) - M) / (1 - e * cos(E))
E = E + d
Loop
This is not very accurate.
Is there some sort of trigonometric expansion or infinite series that would be more accurate?
E - e * sin(E) = M
I can solve this with the Newton Method:
M = 2*pi/3
e = 0.002
E = pi
d = 0.01
Do While SQRT(d^2) > 0.000001
d= (E - e * sin(E) - M) / (1 - e * cos(E))
E = E + d
Loop
This is not very accurate.
Is there some sort of trigonometric expansion or infinite series that would be more accurate?
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